Member 13843522 Ответов: 3

C++: как получить повторный бросок для отображения нового набора случайных чисел в игре в кости?

Я почти закончил с этой программой, кроме того, что я не могу понять, как получить новый набор случайных чисел, когда пользователь выбирает повторный бросок (rolling R при первом запросе). Ниже приведен мой код-может ли кто-нибудь помочь мне выяснить, где я ошибся с синтаксисом, семенем и т. д.?

Что я уже пробовал:

/*
Program Name: P30DiceIfElseLoopRandom.cpp
Name: Amy Kaskowitz
Date Started: 5/24/2018 ; Date completed:
Program Description:
Write a Dice Game program that would result in output like this:

Beat the computer!

You rolled a 2 and a 1 (total =  3)

Do you want to keep those? (y or n)

n

Rolling again....

You rolled a 4 and a 1 (total =  5)

Do you want to keep those? (y or n)

n

Rolling again....

You rolled a 1 and a 1 (total =  2)

Do you want to keep those? (y or n)

y

The computer rolled 6 and 3 (total = 9)

So sorry. You lose.

===

Hint: use random numbers b/w 1-6, make 4 random numbers
*/

#include <stdlib.h> /// need this for srand() -- for random numbers
#include <time.h> /// need this for time() -- time
#include <iostream>  /// need this for cout<< and cin>>
using namespace std; /// need this for cout<< and cin>>

int main()
{
    int iseed = (int)time(0);
    srand(iseed);

    cout << "Beat the computer! \n";

    int roll1 = 1+rand()%6; /// make a random number for die # 1 for user
    int roll2 = 1+rand()%6; /// make a random number for die # 2 for user
    int UserRoll = roll1 + roll2; /// totals the sum of die 1 and die 2 for the user
    char keep;

    do
    {
    cout << "You rolled a " << roll1 << " and a " << roll2 << " for a total of: " << UserRoll << "\n";
    cout << "\n";

        do
        {
        cout << "Would you like to keep this total, or roll again? \n";
        cout << "\n";
        cout << "Enter \"K\" for keep and \"R\" for roll again: \n";
        cin >> keep;

            if (keep != 'K' && keep != 'R')

            {
                cout << "That is not a valid choice. Please choose Y to keep your total or N to roll again. " << endl;
                cout << "\n";
            }

            } while(keep != 'K' && keep != 'R');



            if (keep == 'R')
            {
                cout << "You chose R--let's roll again. \n";
            }


            else
            {
            cout << "Great! Your total is " << UserRoll << "\n";
            }
        } while (keep == 'R');

    int roll3 = 1+rand()%6; /// make a random number for die # 1 for computer
    int roll4 = 1+rand()%6; /// make a random number for die # 2 for computer
    int ComputerRoll = roll3 + roll4; /// totals the sum of die 1 and die 2 for the computer


    cout << "The computer rolled a " << roll3 << " and a " << roll4 << " for a total of: " << ComputerRoll << "\n";
    cout << "\n";

    if (ComputerRoll < UserRoll)
    {
        cout << "Congratulations! You won! \n";
    }

    if (ComputerRoll > UserRoll)
    {
        cout << "Sorry. You lose. \n";
    }

    if (ComputerRoll == UserRoll)
    {
        cout << "It's a tie. \n";
    }

return 0;
}

/*
SAMPLE RUNS:
------------
Beat the computer!
You rolled a 4 and a 6 for a total of: 10

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
R
You chose R--let's roll again.
You rolled a 4 and a 6 for a total of: 10

Would you like to keep this total, or roll again?

Enter "K" for keep and "R" for roll again:
K
Great! Your total is 10
The computer rolled a 4 and a 6 for a total of: 10

It's a tie.

Process returned 0 (0x0)   execution time : 8.763 s
Press any key to continue.

*/

3 Ответов

Рейтинг:
1

Patrice T

Цитата:
Я почти закончил с этой программой, кроме того, что я не могу понять, как получить новый набор случайных чисел, когда пользователь выбирает повторный бросок (rolling R при первом запросе)

Вам нужно потренировать логику, простой метод-взять выходной сигнал и отметить, что происходит за капотом.
say game greetings
// Beat the computer!
roll user dices
say user score
// You rolled a 2 and a 1 (total =  3)
say want to keep ?
// Do you want to keep those? (y or n)
get answer
// n
say roll again
// Rolling again....
roll user dices
say user score
// You rolled a 4 and a 1 (total =  5)
say want to keep ?
// Do you want to keep those? (y or n)
get answer
// n
say roll again
// Rolling again....
roll user dices
say user score
// You rolled a 1 and a 1 (total =  2)
say want to keep ?
// Do you want to keep those? (y or n)
get answer
// y
roll computer dices
say computer score
// The computer rolled 6 and 3 (total = 9)
say winner
// So sorry. You lose.

Теперь проанализируйте его и определите, что входит в lop, а что нет.
Такова структура вашей программы. Все, что отличается в вашем коде, является структурной ошибкой.
Хорошее чтение от известных авторов: Структурного Программирования.формат PDF[^]

Рейтинг:
0

Richard MacCutchan

Создайте функцию, которая выполняет прокатку, и позвольте ей принять параметр, который говорит ей, следует ли заполнять рандомизатор или нет:

int DiceRoll(bool seed = false)
{
    if (seed)
    {
        // seed the randomiser
        srand((int)time(0));
    }

    int roll = 1+rand()%6; // get a random number between 1 and 6

    return roll;
}

// ... in your main loop
    int roll1 = DiceRoll(true);
    while (doing some actions)
    {
        int roll2 = DiceRoll();
        // more code
    }
// ...

Рейтинг:
0

CPallini

Попробуй

#include <cstdlib> /// need this for srand() -- for random numbers
#include <ctime> /// need this for time() -- time
#include <iostream>  /// need this for cout<< and cin>>
using namespace std; /// need this for cout<< and cin>>

int main()
{
    srand(time(0));
    cout << "Beat the computer! \n";
    char playAgain;

    do
    {
      int roll1;
      int roll2;
      int UserRoll;
      char keep;
      do
      {
        roll1 = 1+rand()%6; /// make a random number for die # 1 for user
        roll2 = 1+rand()%6; /// make a random number for die # 2 for user
        UserRoll = roll1 + roll2; /// totals the sum of die 1 and die 2 for the user
        cout << "You rolled a " << roll1 << " and a " << roll2 << " for a total of: " << UserRoll << "\n\n";
        cout << "Would you like to keep this total, or roll again? \n";
        cout << "\n";
        while (true)
        {
          cout << "Enter \"K\" for keep and \"R\" for roll again: \n";
          cin >> keep;

          if (keep == 'K' || keep == 'R') break; // exit the loop

          cout << "That is not a valid choice. Please choose Y to keep your total or N to roll again.\n\n";
        }

        if (keep == 'R')
          cout << "You chose R--let's roll again. \n";
         else
           cout << "Great! Your total is " << UserRoll << "\n";
       } while (keep == 'R');

      int roll3 = 1+rand()%6; /// make a random number for die # 1 for computer
      int roll4 = 1+rand()%6; /// make a random number for die # 2 for computer
      int ComputerRoll = roll3 + roll4; /// totals the sum of die 1 and die 2 for the computer

      cout << "The computer rolled a " << roll3 << " and a " << roll4 << " for a total of: " << ComputerRoll << "\n\n";

      if (ComputerRoll < UserRoll)
        cout << "Congratulations! You won! \n";
      else if (ComputerRoll > UserRoll)
        cout << "Sorry. You lose. \n";
      else //if (ComputerRoll == UserRoll)
        cout << "It's a tie. \n";

      cout << "Enter \"Y\" to play again, any other value to quit.\n";
      cin >> playAgain;
    } while (playAgain =='Y');
}