Как мне сделать расшифровку?

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Я закончил делать шифрование, и это работает, но я не знаю, как сделать расшифровку. Я пробовал делать ut, но результат не тот.
Может ли кто-нибудь исправить мой код?


Ниже приведен код того, что я сделал

Что я уже пробовал:

package oops;

import java.util.Arrays;
import java.util.Map;

import java.util.Scanner;  

public class Main {

	private static final String Bforce = null;
	private static final String BMessage = null;  

	public static void main(String[] args) {

		System.out.println("----Vigenere Cipher Encryptor----\n");
		Scanner in = new Scanner(System.in); 



		//	Allow the user to choose if they want to encrypt or decrypt or brute force a message
		System.out.println(" 1 to encrypt a message  ");
		System.out.println(" 2 to decrypt a message  ");
		System.out.println(" 3 to brute force  ");
		int input = in.nextInt();

		// ENCRYPT MESSAGE 
		if (input == 1) {
			System.out.print("Enter the password: ");
			String key = in.next();
			// key number
			System.out.print("Enter the key number (1-26) : ");
			int number = in.nextInt();   

			if (number >= 1 && number <= 26) { 

			}

			else { 


			}


			// message
			System.out.print("Enter the message : ");
           
			String EMessage = in.next();
			String encryptMessage = encrypt(EMessage, key, number);
			 System.out.println("The encrypted message is: " + encryptMessage);
			//for (int x = 0; x <= number; x++) {
		//	replaceAll("[-+.^:,]","");  
			// encrypt the message
   //		String encryptMessage = encrypt(EMessage, key);
		//	System.out.println("The encrypted message is: " + encryptMessage);
			

		
		}

		// DECRYPT MESSAGE option 2
		else if (input == 2) {
			System.out.print("Enter the password: ");
			String key = in.next(); 
			// key number
			System.out.print("Enter the key number (1-26) : ");

			// NUM 1- 26  OR ELSE IT GIVES AN ERROR
			int number = in.nextInt();   

			if (number >= 1 && number <= 26) { 

			}

			else { 


			}



			// prompt for message
			System.out.print("Enter the message: ");
			String dMessage = in.next(); 
			String decryptMessage = decrypt(dMessage, key, number); 
			System.out.println("The decrypted message is: " + decryptMessage);
			//for (int x = 0; x <= number; x++) {
			//replaceAll("[-+.^:,?_-`*/()]","");   
				// decrypt the message
			////	String DecryptMessage = decrypt(DMessage, key);
	//	System.out.println("The decrypted message is: " + decryptMessage);

				// brute force option 3
			
		}
		
		
		else if  (input == 3) {
			System.out.print("Enter the password: ");
			String password = in.next(); 
			// key number
			System.out.print("Enter the key number (1-26) : ");

			// 1-26 OR ELSE ERROR
			int number = in.nextInt();   

			if (number >= 1 && number <= 26) { 

			}

			else { 


			}

			// message  for user
			System.out.print("Enter the message: ");
			String BMessage = in.next(); 

			for (int x = 0; x <= number; x++) {
				replaceAll("[-+.^:,]","");  
				// decrypt w brute force
				String BruteMessage = Bforce(BMessage, password);
				System.out.println("The decrypted message is: " + BruteMessage);
			}
		}
		else {
			System.out.println("Wrong Input!");
		}
		in.close();
	}








	private static void replaceAll(String string, String string2) {
		

	}





	//	Encryption 1
	//	Encryption Logic: 

	public static String encrypt(String Message, String Key, int number) {
		
		String eMessage = "";
		Message = Message.toUpperCase();
		Key = Key.toUpperCase(); 
		
		for (int i = 0, j = 0; i < Message.length(); i++) {
			// Get the character from the message
			char letter = Message.charAt(i);
			// Get the ASCII value of the character
			int ascii = (int) letter;
			// Get the value of the character in the password
			int passVal = (int) (Key.charAt(j)) - 65;
			// Calculate the amount of the shift
			int shiftPos = ascii + passVal - number;
			
			// Check if the position is > 90 (that is, past the letter 'Z')
			if (shiftPos > 90) {
				// Go back  to the letter 'A'
				eMessage += (char) (shiftPos % 90 + 64);
			}
			else {
				// Take the character at the shift position
				eMessage += (char) (ascii + passVal - number);
			}
		//	System.out.println(EMessage);
			j = ++j % Key.length();
		}
		return eMessage;
	}

	//	Decryption 2
	//	Decryption Logic: 
	public static String decrypt(String Message, String Key, int number) {
		String dMessage = ""; 
		Message = Message.toLowerCase();
		Key = Key.toLowerCase();     
		
			for (int i = 0, j = 0; i < Message.length(); i++) {
				char letter = Message.charAt(i); 
				int num = (int) letter; 
				int pass = (int) (Key.charAt(j)) - 'a';

				int shiftPos = num - pass + number; 
				if (shiftPos > 90) {
					// Go back  to the letter 'A'
					dMessage += (char) (shiftPos % 90 - 64);
				}
				else {			

				
					dMessage += (char) (num - pass + number);
				}
				dMessage += (char)((num - pass - number) % 26 + 65);
				j = ++j % Key.length();
				dMessage =  dMessage.replaceAll("[^a-zA-Z0-9]", "");
			}  
	

		  	
		
		
					return dMessage;
			
			
			}
	

	// BRUTE FORCE  3     


	public static <Bmessage> String Bforce(String Message, String key) {
		String BMessage = "";
		Message = Message.toLowerCase(); 
		for (int i = 0, j = 0; i < Message.length(); i++) {
			char letter = Message.charAt(i);
			BMessage += (char)((letter - key.charAt(j) + 26) % 26 + 65);
			j = ++j % key.length();
		}


		return BMessage.replaceAll("[", "");



	}
}

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