Как пропустить день, когда в C нет открытия магазина#

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I am trying to create a program that will skip the days when there is no store opening on that day.

Ex:
Day 1 -> Friday
DAy 2 -> Saturday
Day 3 -> Sunday (no store opening)
Day 4 -> Monday

Currently my program will skip and add 1 day when there is no store opening. so it will be like this:

Day 3 -> Sunday + 1day = Monday, 

but my problem is.. the Day 4 which also scheduled on Monday,.

so my actual result will become :

Day 3 -> Monday
Day 4 -> Monday (which must be move on Tuesday)

What can I do to achieve that?

Что я уже пробовал:

Here is my code:

    var dayOne = td.MinutesFromAttached.Value - 1;

                    for (var i = 0; i <= 3; i++)
                    {
                        var possibleDate = context.FirstDay.AddDays(dayOne + i);

                        if (!_storeScheduleService.IsStoreOpenForDate(storeId, possibleDate)) continue;

                        var scheduleCheck = _storeScheduleService.IsStoreOpen(context.TaskParam.Customer.StoreId.Value, possibleDate);

                        var tsDispatch = td.DispatchTime ?? new TimeSpan(9, 0, 0);

                        if (tsDispatch < scheduleCheck.Schedule.Open)
                        {
                            tsDispatch = scheduleCheck.Schedule.Open.Value;
                        }
                        else if (tsDispatch > scheduleCheck.Schedule.Close)
                        {
                            tsDispatch = scheduleCheck.Schedule.Close.Value;
                        }

                        var dateTimeSchedule = new DateTime(possibleDate.Year,
                            possibleDate.Month,
                            possibleDate.Day,
                            tsDispatch.Hours,
                            tsDispatch.Minutes,
                            tsDispatch.Seconds);

                        aTaskExec.ScheduledDispatchedDateTime = dateTimeSchedule;

                        break;
                    }
    ```

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