Как сделать динамический класс все индивидуально вывода в PHP-цикл while через jQuery
у меня есть проект, в котором я извлечения вывода из базы данных через PHP цикл while теперь у меня реакция столбца, в каждый выходной теперь, когда пользователь нажимает на реагировать кнопки я хочу, чтобы изменить значение дел, связанных с выходом только но моя проблема в том что когда я нажимаю на кнопку он реагирует изменения значений всех дел, имеющих класс react2
это мой код.
$query = "SELECT ph.likes, ph.image_url,ph.email,ph.username,ph.uid ,ph.id,ph.avatar_path
FROM photos as ph
inner join followers as fol
on fol.user_id = ph.uid
where fol.uid = '$id'
ORDER BY ph.image_url DESC ";
$fire = mysqli_query($con,$query) or die("can not fetch data from database ".mysqli_error($con));
if (mysqli_num_rows($fire)>0) {
while ($users = mysqli_fetch_assoc($fire)) {
$likes = $users['likes'];
$username = $users['username'];
$uid = $users['uid'];
$pixid = $users['id'];
$avatar_path5 = $users['avatar_path'];
?>
<div class="all" >
<div class="card" >
<div class="float" >
<div class="avatar" >
<img src="<?php echo $avatar_path5; ?>" width="100%" class="avatar">
</div>
<div class="username" style="font-weight: 600; size: 14px; text-decoration: none;">
<p><?php echo "<div><a href='users.php?id=".$users['uid']."'>
<h3>".$users['username']."</h3>
</div></a>"; ?></p>
</div>
</div>
<img src="<?php echo $users['image_url']?>" alt="Avatar" style="width:682px;">
<div class="container">
<h4><?php echo "<div><a href='users.php?id=".$users['uid']."'>
</div></a>";?></h4>
</div>
<span id="count" class="likes_count"><?php echo $users['likes']; ?> likes</span>
<div style="padding: 2px; margin-top: 5px;">
<?php
if (isset($_POST['liked'])) {
$postid = $_POST['postid'];
$result = mysqli_query($con, "SELECT * FROM photos WHERE id=$postid")or die(mysqli_error($con));
$row = mysqli_fetch_array($result)
or die(mysqli_error($con));
$n = $row['likes'];
mysqli_query($con, "INSERT INTO likes (user_id,username, post_id) VALUES ($id, '$fullname', $postid)")or die(mysqli_error($con));
mysqli_query($con, "UPDATE photos SET likes=$n+1 WHERE id=$postid")or die(mysqli_error($con));
echo $n+1;
exit();
}
if (isset($_POST['unliked'])) {
$postid = $_POST['postid'];
$result = mysqli_query($con, "SELECT * FROM photos WHERE id=$postid")or die(mysqli_error($con));
$row = mysqli_fetch_array($result)or die(mysqli_error($con));
$n = $row['likes'];
mysqli_query($con, "DELETE FROM likes WHERE post_id=$postid AND user_id=$id")or die(mysqli_error($con));
mysqli_query($con, "UPDATE photos SET likes=$n-1 WHERE id=$postid")or die(mysqli_error($con));
echo $n-1;
exit();
}
?>
</div>
<div>
<?php
// determine if user has already liked this post
$results = mysqli_query($con, "SELECT * FROM likes WHERE user_id=$id AND post_id=".$users['id']."")or die(mysqli_error($con));
if (mysqli_num_rows($results) == 1 ): ?>
<!-- user already likes post -->
<span class="unlike fas fa-heart animated bounceIn" data-id="<?php echo $users['id']; ?>"></span>
<span class="like hide far fa-heart" onclick="PlaySound()" data-id="<?php echo $users['id']; ?>"></span>
<?php else: ?>
<!-- user has not yet liked post -->
<span class="like far fa-heart" onclick="PlaySound()" data-id="<?php echo $users['id']; ?>"></span>
<span class="unlike hide fas fa-heart animated bounceIn" data-id="<?php echo $users['id']; ?>"></span>
<?php endif ?>
<a class="com" style="color: #929292 !important; " href="show.php?post_id=<?php echo $users['id'];?>" style=""> <span class="glyphicon glyphicon-comment trigger" ></span>comments</a>
<div class="wink" id="ex2" style=" color: black;
width: 30px;
height: 30px;
margin-top: -20px;
margin-left: 209px;
" > <?php
$query2 = "SELECT * FROM gormint where post_id = $pixid and user_id= $id3";
$fire2 = mysqli_query($con,$query2) or die("can not fetch data from database ".mysqli_error($con));
$query3 = "SELECT * FROM bhai where post_id = $pixid and user_id= $id3";
$fire3 = mysqli_query($con,$query3) or die("can not fetch data from database ".mysqli_error($con));
$query4 = "SELECT * FROM famer where post_id = $pixid and user_id= $id3";
$fire4 = mysqli_query($con,$query4) or die("can not fetch data from database ".mysqli_error($con));
$query5 = "SELECT * FROM muskan where post_id = $pixid and user_id= $id3";
$fire5 = mysqli_query($con,$query5) or die("can not fetch data from database ".mysqli_error($con));
if (mysqli_num_rows($fire2)>0) {
echo "<img src='gormint.jpg' class='gormint2' >";
}elseif (mysqli_num_rows($fire3)>0) {
echo "<img src='bhai.jpg' class='bhai2'>";
}elseif (mysqli_num_rows($fire4)>0) {
echo "<img src='famer.jpg' class='bhai2'>";
}elseif (mysqli_num_rows($fire5)>0) {
echo "<img src='zakhir.jpg' class='bhai2'>";
} else{
echo "<img src='wink.png' class='wink2'>";
}
?></div>
<div class="flipClass" id="flip">react</div>
<div class="panelClass" id="panel">
<input type="image" onclick="PlaySound2()" id="display" data-value="<?php echo $users['id'];?>" src="gormint2.jpg" class="close2 display gormint animated bounceIn " >
<input type="image" onclick="PlaySound3()" data-value="<?php echo $users['id'];?>" id="display2" src="bhai.jpg" class="close2 display2 bhai animated bounceIn">
<input type="image" onclick="PlaySound4()" data-value="<?php echo $users['id'];?>" id="display3" src="famer.jpg" class="close2 display3 bhai animated bounceIn">
<input type="image" onclick="PlaySound5()" data-value="<?php echo $users['id'];?>" id="display4" src="zakhir.jpg" class="close2 display4 bhai animated bounceIn">
</div>
</div>
</div>
<?php
}
}
?>
& это мой сценарий
$('.display').click(function(){
var value=$(this).attr('data-value');
$.ajax({url:"reaction.php?pollid="+value,cache:false,
success:function(result){
$('.react2').load('img.php?id=<?php echo $users['id'];?>');
}});
});
$('.display2').click(function(){
var value=$(this).attr('data-value');
$.ajax({url:"reaction2.php?pollid="+value,cache:false,
success:function(result){
$('.react2').load('bhai.php?id=<?php echo $users['id'];?>');
}});
});
$('.display3').click(function(){
var value=$(this).attr('data-value');
$.ajax({url:"reaction3.php?pollid="+value,cache:false,
success:function(result){
$('.react2').load('famer.php?id=<?php echo $users['id'];?>');
}});
});
$('.display4').click(function(){
var value=$(this).attr('data-value');
$.ajax({url:"reaction4.php?pollid="+value,cache:false,
success:function(result){
$('.react2').load('zakhir.php?id=<?php echo $users['id'];?>');
}});
});
Что я уже пробовал:
я искал на форумах там они предложили мне использовать $(это) но я не понимаю, как использовать $(это) в нем plzz помогите мне