Как сделать так, чтобы мои кнопки like работали

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When i submit my review and through ajax succes, reload comment div only.. it gets submitted but like and dislike button stop working and works only when i reload the whole page. How can i fix this?

<!--CID like -->
<script>
$(document).ready(function(){
$(".count2").click(function(){
 var id = $(this).attr("name");
var c = "counter2";
c = c + id;
 saveData(c,id);

$("#" + c).load();
});
function saveData(c,x){  
$.ajax({
       type: "POST",
   url: "Ccounter.php",
   data: { count: "1", id : x}
    })
    .done(function( count ) {
   $("#" + c).html(count);
    })
    .fail(function() {
   // alert( "error" );
    });
}
});
</script>
<!-- like -->


<!--CID dislike -->
<script>
$(document).ready(function(){
$(".count3").click(function(){
 var id = $(this).attr("name");
var c = "counter3";
c = c + id;
 saveData(c,id);


$("#" + c).load();
});
function saveData(c,x){  
$.ajax({
       type: "POST",
   url: "Cdecounter.php",
   data: { count: "1", id: x }
    })
    .done(function( count ) {
   $("#" + c).html(count);
    })
    .fail(function() {
   // alert( "error" );
    });
}
});
</script>
<!-- dislike -->

<?php 
								require_once __DIR__ . "/config.php";
								$star->id = "index_page";
								include "database.php";
								$sql ="SELECT * FROM review where prod_Id = '$prodId' ORDER BY CID DESC"; 
								$query = mysqli_query($conn,$sql);
								// output data of each row
								while($row = mysqli_fetch_assoc($query))
								{
									
									$cid= $row["CID"];
									$id = $row["CID"];
									$name = $row["Name"];
									$comm = $row["Comment"];
								
									?>
								
								
							 <div class="media" style="width:100%;height:100%;  border-color:#000000; border-radius: 5px;box-shadow: 5px 5px 5px #888888;">
								<div style="float:right;">
								<?php
									echo  $star->getRating("size-2");
								?>
								</div>
							<h5 style="display:inline-block;margin-bottom:0.4em;font-size:4;font-size: 25px;color:#6d7585">  <?php echo $name;?></h5>
								<div class="media-left">
									<a href="">
									<img src="images/user.jpg" title="User" alt=" " />
									</a>
								</div>
								<div class="media-body">
								<?php	
									echo "<p>".$comm."</p>";
									echo "<span><a id='count2' class='count2' name='".$id."'><img src='images/Like.png' width='20px' height='20px' title='Like' alt=' ' /></a>  ";
									?>
									<div id="counter2<?php echo $id;?>" style="width:10px;display:inline-block;margin-right:15px;">
									<?php
										$fetch1=mysqli_query($conn,"select `Up` from review where CID = '$cid'");
										$fetch2=mysqli_fetch_array($fetch1);
										$counter=$fetch2['Up'];
										echo $counter;
										echo "</div><a id='count3' class='count3' name='".$id."'><img src='images/Dislike.png' width='20px' height='20px' title='DisLike' alt=' ' /></a>  ";
										?>
									<div id="counter3<?php echo $id;?>" style="width:10px;display:inline-block;margin-right:10px;">	
										<?php
										$fetch1=mysqli_query($conn,"select `Down` from review where CID = '$cid'");
										$fetch2=mysqli_fetch_array($fetch1);
										$counter=$fetch2['Down'];
										echo $counter;
										echo"</div>  <a  onclick = 'showForm(1".$id.")' >Reply   </a><a onclick = 'showForm1(2".$id.")' >Edit   </a><span style='float:right;'>".$row['Time_Stamp']."  </span></span>";
									include('reply.php');
									include('edit.php');
									echo "</div>
											<br>
								</div>";

Что я уже пробовал:

я пытался перезагрузить различные div по очереди, но каждый раз терпел неудачу.

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