LoginForm, который будет с Java
Форма входа. В основном он будет просить пользователя ввести имя пользователя и пароль и сравнить его со списком имен пользователей и паролей в users.txt , если он найдет правильное имя пользователя и пароль, форма изменится на "login Successful".
Просто в целях тестирования я подумал, что было бы интересно увидеть значение usernameField. getText (), но проблема в том, что независимо от того, как я отлаживаю программу, я не достигну этих двух строк кода:
Строка inputUsername = usernameField. getText (). toLowerCase();
Строка inputPassword = passwordField. getText();
/* * To change this license header, choose License Headers in Project Properties. * To change this template file, choose Tools | Templates * and open the template in the editor. */ //package emptyframeviewer; /** * * @author ACER */ import java.awt.CardLayout; import java.awt.FlowLayout; import java.awt.GridLayout; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import java.io.File; import java.io.FileNotFoundException; import java.util.HashMap; import java.util.Map; import java.util.Scanner; import javax.swing.JButton; import javax.swing.JFrame; import javax.swing.JLabel; import javax.swing.JOptionPane; import javax.swing.JPanel; import javax.swing.JPasswordField; import javax.swing.JTextField; /*Business P11.26 Write a program with a graphical interface that implements a login window with text fields for the user name and password. When the login is successful, hide the login window and open a new window with a welcome message. Follow these rules for validating the password: 1. The user name is not case sensitive. 2. The password is case sensitive. 3. The user has three opportunities to enter valid credentials. Otherwise, display an error message and terminate the program. When the program starts, read the file users.txt . Each line in that file contains a username and password, separated by a space. You should make a users.txt file for testing your program. Business P11.27 In Exercise P11.26, the password is shown as it is typed. Browse the Swing documentation to find an appropriate component for entering a password. Improve the solution of Exercise P11.26 by using this component instead of a text field. Each time the user types a letter, show a ■ character.*/ @SuppressWarnings("serial") public class LoginFrame extends JFrame { private static final int FRAME_WIDTH = 300; private static final int FRAME_HEIGHT = 200; private HashMap<string, string=""> usernamesAndPasswords; private JTextField usernameField; private JTextField passwordField; private JButton loginButton; private JPanel loginPanel; private JPanel welcomePanel; private JPanel mainPanel; private CardLayout cardLayout; public LoginFrame() { this.createComponents(); super.setTitle("Login Panel"); super.setSize(FRAME_WIDTH, FRAME_HEIGHT); super.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); super.setVisible(true); } private void createComponents() { this.mainPanel = new JPanel(new CardLayout()); this.createHashMap(); this.loginPanel = this.createLoginPanel(); this.welcomePanel = this.createWelcomePanel(); this.mainPanel.add(this.loginPanel, "LoginPanel"); this.mainPanel.add(this.welcomePanel, "WelcomePanel"); this.cardLayout = (CardLayout) this.mainPanel.getLayout(); this.cardLayout.show(this.mainPanel, "LoginPanel"); super.add(this.mainPanel); } private JPanel createLoginPanel() { JPanel panel = new JPanel(new GridLayout(3, 2)); this.loginButton = new JButton("Login"); final int TEXT_FIELD_SIZE = 10; this.usernameField = new JTextField(TEXT_FIELD_SIZE); this.passwordField = new JPasswordField(TEXT_FIELD_SIZE); this.loginButton.addActionListener(new ActionListener() { private int loginAttempts = 3; @Override public void actionPerformed(ActionEvent arg0) { boolean loggedIn = false; String inputUsername = usernameField.getText().toLowerCase(); String inputPassword = passwordField.getText(); if (this.loginAttempts == 1) { JOptionPane.showMessageDialog(null, "Number of login attemtps exceeded. Exitting..."); System.exit(1); } for (Map.Entry<string, string=""> validUser : usernamesAndPasswords.entrySet()) { if (inputUsername.equals(validUser.getKey().toLowerCase())) { if (inputPassword.equals(validUser.getValue())) { System.out.println("Login successful!"); cardLayout.show(mainPanel, "WelcomePanel"); loggedIn = true; } } } if (!loggedIn) { this.loginAttempts -= 1; String message = String.format("Invalid username/password. %d %s remaining", this.loginAttempts, (this.loginAttempts > 1) ? "attempts" : "attempt"); JOptionPane.showMessageDialog(null, message, "LOGIN FAILED", JOptionPane.INFORMATION_MESSAGE); } } }); panel.add(new JLabel("Username")); panel.add(this.usernameField); panel.add(new JLabel("Password")); panel.add(this.passwordField); panel.add(this.loginButton); return panel; } private JPanel createWelcomePanel() { JPanel panel = new JPanel(new GridLayout(3, 1)); panel.add(new JLabel("Welcome")); panel.add(new JButton("Change password")); JButton logoutBtn = new JButton("Logout"); logoutBtn.addActionListener(new ActionListener() { @Override public void actionPerformed(ActionEvent arg0) { System.exit(0); } }); panel.add(logoutBtn); return panel; } private void createHashMap() { this.usernamesAndPasswords = new HashMap<string, string="">(); try { Scanner fileScanner = new Scanner(new File("users.txt")); while (fileScanner.hasNextLine()) { String[] line = fileScanner.nextLine().split(" "); this.usernamesAndPasswords.put(line[0], line[1]); System.out.println(line[0] + " " + line[1]); } fileScanner.close(); } catch (FileNotFoundException e) { JOptionPane.showMessageDialog(null, "Error: no users.txt file found. No users/passwords available to read.", "USERS.TXT NOT FOUND!", JOptionPane.ERROR_MESSAGE); e.printStackTrace(); } } public static void main(String[] args) { JFrame testFramee = new LoginFrame(); } }
Что я уже пробовал:
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Richard MacCutchan
Что на самом деле происходит, когда вы нажимаете кнопку входа в систему, запускает ли она действие?
forte74
форма просто полностью отмирает, кнопка входа в систему заглохла. Я не уверен насчет Eclipse , но в Visual Studio, когда вы нажимаете login, он переходит к методу void actionperformed, который мне нужен.