Почему мой код не дает результата. Он вводит цифры, после нажатия клавиши enter он ничего не показывает...
#include<stdio.h> int main() {int a,b,c; printf("enter value of numbers "); scanf("%d %d %d ", &a,&b,&c); if((a>b)&&(a>c)) { if(b>c) printf("no in descending order are %d %d %d",a,b,c); else printf("no in descending order are %d %d %d",a,c,b ); } else if((b>a)&&(b>c)) { if(a>c) printf("no in descending order are %d %d %d",b,a,c); else printf("no in descending order are %d %d %d",b,c,a); } else if((c>a)&&(c>b)) { if(a>b) printf("no in descending order are %d %d d",c,a,b); else printf("no in descending order are %d %d %d ",c,b,a); } return 0; }
Что я уже пробовал:
#include<stdio.h> int main() {int a,b,c; printf("enter value of numbers "); scanf("%d %d %d ", &a,&b,&c); if((a>b)&&(a>c)) { if(b>c) printf("no in descending order are %d %d %d",a,b,c); else printf("no in descending order are %d %d %d",a,c,b ); } else if((b>a)&&(b>c)) { if(a>c) printf("no in descending order are %d %d %d",b,a,c); else printf("no in descending order are %d %d %d",b,c,a); } else if((c>a)&&(c>b)) { if(a>b) printf("no in descending order are %d %d d",c,a,b); else printf("no in descending order are %d %d %d ",c,b,a); } return 0; }