Проверьте мой алгоритм кодирования функции 'xdateago'

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Function xDateAgo(ByVal D As Date, Optional ByVal StatusWord As String = "Created") As String
        Dim Expr$ = StatusWord + " at "
        Dim Hours, Minutes, Seconds, Days, Weeks, Months, Years As Integer
        Dim OldMonthDays, CurrentMonthDays, PlusDays As Integer
        Dim Value() As String = {"", "", "", ""}
        Dim x% = 0
6:      Years = 0
        Months = 0
        OldMonthDays = DateTime.DaysInMonth(D.Year, D.Month) - DatePart(DateInterval.Day, D)
        CurrentMonthDays = DatePart(DateInterval.Day, Now)
        If Now.Year = D.Year Then
            Select Case D.Month
                Case Is = Now.Month
                    PlusDays = CurrentMonthDays - DatePart(DateInterval.Day, D)
                Case Is < Now.Month
                    Months = DateDiff(DateInterval.Month, DateSerial(D.Year, D.Month, DateTime.DaysInMonth(D.Year, D.Month)), DateSerial(Now.Year, Now.Month, 1))
                    If CurrentMonthDays >= DatePart(DateInterval.Day, D) Then
                        PlusDays = (CurrentMonthDays) - DatePart(DateInterval.Day, D)
                    ElseIf OldMonthDays + CurrentMonthDays >= DateTime.DaysInMonth(D.Year, D.Month) Then
                        PlusDays = (OldMonthDays + CurrentMonthDays) - DatePart(DateInterval.Day, D)
                    Else
                        PlusDays = OldMonthDays + CurrentMonthDays
                    End If
            End Select
        ElseIf Now.Year > D.Year Then
            Years = DateDiff(DateInterval.Year, D, Now)
            Months = DateDiff(DateInterval.Month, DateSerial(D.Year, D.Month, DateTime.DaysInMonth(D.Year, D.Month)), DateSerial(Now.Year, Now.Month, 1))
            If Months >= (Years * 12) Then
                Months = Months - (Years * 12)
            End If
            If Months / 12 <= Years Then
                Years = Years - Months / 12
            End If
            PlusDays = CurrentMonthDays
            If CurrentMonthDays >= DatePart(DateInterval.Day, D) Then
                PlusDays = (CurrentMonthDays) - DatePart(DateInterval.Day, D)
            ElseIf OldMonthDays + CurrentMonthDays >= DateTime.DaysInMonth(D.Year, D.Month) Then
                PlusDays = (OldMonthDays + CurrentMonthDays) - DatePart(DateInterval.Day, D)
            Else
                PlusDays = OldMonthDays + CurrentMonthDays
                Months -= 1
            End If
        End If
        Weeks = (PlusDays \ 7)
        Days = If(PlusDays >= 7, PlusDays Mod 7, PlusDays)

        If Years > 0 Then
            Value(0) = String.Format("{0} Year{1}", Years, If(Years > 1, "s", ""))
        End If
5:      If CBool(Months > 0) Then
            Value(1) = String.Format("{0} Month{1}", Months, If(Months > 1, "s", ""))
        End If
        If CBool(Weeks > 0) Then
            Value(2) = String.Format("{0} Week{1}", Weeks, If(Weeks > 1, "s", ""))
        End If
        ' { to take x Time ago...
        Dim T1, T2, T3 As TimeSpan
        T1 = D.TimeOfDay
        T2 = Now.TimeOfDay
        Hours = ((24 - T1.Hours) + T2.Hours) - 1
        Minutes = ((60 - T1.Minutes) + T2.Minutes) - 1
        Seconds = ((60 - T1.Seconds) + T2.Seconds)
        T3 = New TimeSpan(Hours, Minutes, Seconds)
        If T2 < T1.Add(New TimeSpan(0, 0, -1)) Then
            Days -= 1
        End If
        Hours = T3.Hours
        Minutes = T3.Minutes
        Seconds = T3.Seconds
        ' ...}
        If CBool(Days > 0) Then
            Value(3) = String.Format("{0} Day{1}", Days, If(Days > 1, "s", ""))
        End If
        For Each v As String In Value
            If v.Length > 0 Then
                Expr += String.Format(If(x = 0, "{0}", "{1}{0}"), v, ", ")
                x += 1
            End If
        Next
        Expr += String.Format("{1}{0}", Format(TimeSerial(Hours, Minutes, Seconds), "HH:mm:ss"), _
                              If(Years > 0 Or Months > 0 Or Days > 0 Or Weeks > 0, " and ", ""))

        Expr += " ago"
        Return Expr
    End Function

Что я уже пробовал:

Пожалуйста, проверьте мой алгоритм кодирования, чтобы сделать его лучше

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