Clifford Nelson
Это должен быть ручной процесс. Пример того, что я сделал для экспорта Excel:
private static void Excel(string fileName, List<IDirectoryInventoryDataCollector> list)
{
try
{
var xlApp = new Excel.Application();
var xlWorkBook = xlApp.Workbooks.Add();
var xlWorkSheet = (Excel.Worksheet)xlWorkBook.Worksheets.get_Item(1);
ExcelTitleRow(list[0], 1, xlWorkSheet);
int row = 2;
foreach (var item in list)
{
ExcelFillRow(item, row++, xlWorkSheet);
}
for (int i = 1; i < list[0].MaxLevel - 1; i++)
{
((Range)xlWorkSheet.Columns[i]).ColumnWidth = 2;
}
((Range)xlWorkSheet.Columns[list[0].MaxLevel - 1]).ColumnWidth = 30;
((Range)xlWorkSheet.Rows[1]).WrapText = true;
((Range)xlWorkSheet.Rows[1]).HorizontalAlignment = HorizontalAlignment.Center;
((Range)xlWorkSheet.Cells[1, 1]).WrapText = false;
xlWorkBook.SaveAs(fileName);
xlWorkBook.Close();
xlApp.Quit();
}
catch (AccessViolationException)
{
System.Windows.Forms.MessageBox.Show(
"Have encountered access violation. This could be issue with Excel 2000 if that is only version installed on computer",
"Access Violation");
}
catch (Exception)
{
System.Windows.Forms.MessageBox.Show("Unknown error",
"Unknown error");
}
}
private static void ExcelFillRow(IDirectoryInventoryDataCollector item, int row, Excel.Worksheet sheet)
{
sheet.Cells[row, item.Level] = item.Name;
int column = item.MaxLevel;
foreach (var property in item.GetProperties())
{
sheet.Cells[row, column++] = property;
}
}
private static void ExcelTitleRow(IDirectoryInventoryDataCollector item, int row, Excel.Worksheet sheet)
{
sheet.Cells[row, 1] = "Name";
int column = item.MaxLevel;
foreach (var property in item.GetPropertyNames())
{
sheet.Cells[row, column++] = property;
}
}
Пространство имен, которое вам нужно, это
using Excel = Microsoft.Office.Interop.Excel;
using Microsoft.Office.Interop.Excel;